0=(2y^2)-34y+60

Solution for 0=(2y^2)-34y+60 equation:

0=(2y^2)-34y+60

We move all terms to the left:

0-((2y^2)-34y+60)=0

We add all the numbers together, and all the variables

-(2y^2-34y+60)=0

We get rid of parentheses

-2y^2+34y-60=0

a = -2; b = 34; c = -60;
Δ = b2-4ac
Δ = 342-4·(-2)·(-60)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*-2}=\frac{-60}{-4}
=+15
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*-2}=\frac{-8}{-4}
=+2
$